x^2+800x-704=0

Solution for x^2+800x-704=0 equation:

x^2+800x-704=0

a = 1; b = 800; c = -704;
Δ = b2-4ac
Δ = 8002-4·1·(-704)
Δ = 642816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{642816}=\sqrt{20736*31}=\sqrt{20736}*\sqrt{31}=144\sqrt{31}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(800)-144\sqrt{31}}{2*1}=\frac{-800-144\sqrt{31}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(800)+144\sqrt{31}}{2*1}=\frac{-800+144\sqrt{31}}{2}
$